Not sure how well this works for modern planes, but historic aircraft was essentially made by lofting from a few sections. You can see the shapes and positions of the sections in any decent plan. http://www.fiatcr32.rotorswings.com.au/ I try to create the sections shown in the plan as closely as pos...

I generally begin with cross sections in the same positions that they were on the real aircraft.

I thought about saying that previous CAD experience wouldn't hurt, but from the forum we've seen that previous CAD experience can be either a blessing, curse, or somewhere in between for somebody starting on with FreeCAD - it just depends on the individual. Well, I would definitely avoid saying som...

Create cross sections and use Part - Loft.

I updated Wikipedia in all languages except Persian and Japanese, but I didn't go so far as to change screenshots.

I checked the German release notes, and the first sentence (apart from being in English) still states July 6. Could you please also fix this to get things consistent?

I think July 1 makes much more sense. It was the date announced by wmayer beforehand, and he kept his promise and released a functional stable version on that date. There were people (including me) who installed and started using stable 0.14 on the very first day. It is of minor importance that some...

I am not sure whether this is possible, but I found a rather convoluted way to do something of that sort. First I created four short parallel lines and moved them around space using the positioning window. Then I created a loft through them, which is the curved narrow strip. Then I extracted a curve...

There is an amazing theorem called Archimedes' Hat-Box Theorem, which you might find instructive for this sort of problems. It says that the area of a spherical segment equals the area of its projection on a surrounding cylinder. See the picture at http://mathworld.wolfram.com/ArchimedesHat-BoxTheor...

The revolution doesn't change the result because the surface is proportional to the revolution angle, so the final answer is angle = p * pi / 2, with p in [0, 1]. This is wrong. The result is skewed by the position of each infinitesimal line segment. Take a look at the picture of a spherical cap at...