I want to create a panning tool

[hrhassan]

I want to make a panning tool in the command bar that when selected, will allow the left mouse button be used for panning, so I want it to activate a different navigation style. However, this is only when this command toggle is selected. Once deselected, you can no longer pan using the left mouse button.

WHAT I HAVE TRIED:

• I found CADNavigationStyle.cpp in the Source code and tried modifying the button arrangement.

• Designated a toggle in the Command.cpp and Workspace.cpp

• Created a new Navigation style file that I would like activated when the toggle is selected

Code I tried to create in CommandView.cpp with the init command from SoFCDB.cpp:

Code: Select all

DEF_STD_CMD_AC(StdPanTool)

StdPanTool::StdPanTool()
    : Command("Std_PanTool")
{
    sGroup = QT_TR_NOOP("View");
    sMenuText = QT_TR_NOOP("Pan");
    sToolTipText = QT_TR_NOOP("Panning tool");
    sWhatsThis = "Std_PanTool";
    sStatusTip = QT_TR_NOOP("Pan across canvas");
    eType = 0;
}

Action* StdPanTool::createAction(void)
{
    Action* pcAction = Command::createAction();
    pcAction->setCheckable(true);
    pcAction->setChecked(true);

    return pcAction;
}

void StdPanTool::activated(int iMsg)
{
PanNavigationStyle::init();


bool StdPanTool::isActive()
{
    static bool checked = false;
    if (!checked) {
        Action* act = this->getAction();
        if (act) {
            act->setChecked(getMainWindow()->statusBar()->isVisible());
            checked = true;
        }
    }
    return true;
}

This code gave me the toggle feature, but did not activate nor deactivate the navigation style.

What I would like to know is how I can activate a certain navigation style when the command toggle is selected.

I am compiling with Visual Studio 2019 and LibPack 12.1.4

Thank you.

[chrisb]

Moved from Install/Compile.