[SOLVED] Attach LCS to the midpoint of a line

[PAS_Drafter]

Hi

I'd like to attach my LCS for an assembly to the midpoint of a line. The line could get wider or narrower depending on how the part gets changed, but I want the attachment point to always be the midpoint. See picture.

attachtomidpoint.PNG (38.98 KiB) Viewed 1088 times

I've tried using the two points as shown or just the line. If I select "Inertial CS", it gives me what I want, but then the Report View starts complaining and says the various axis are undefined. I don't like having errors come up so I'm looking for a way to avoid that. If I use the Align O-Z-X when selecting points or Tangent with Z when selecting the line, the axis of the LCS line up the way I want, but it connects to one end of the line.

I can adjust the connection by adjusting the X, Y, or Z direction, but I don't know how to determine what the length of the line is (since it is dynamic) and then use half of it. I am assuming there is a way to use the equation editor to pull the length of the line of the Shapebinder somehow, but I don't have much experience with macros or software side to know what "variable" I'd need to grab.

Is there an easy way to do this?

Thanks

OS: Windows 10 Version 2009
Word size of OS: 64-bit
Word size of FreeCAD: 64-bit
Version: 0.19.24291 (Git)
Build type: Release
Branch: releases/FreeCAD-0-19
Hash: 7b5e18a0759de778b74d3a5c17eba9cb815035ac
Python version: 3.8.6+
Qt version: 5.15.2
Coin version: 4.0.1
OCC version: 7.5.0
Locale: English/United States (en_US)

[Shalmeneser]

* Select line
* Datum LCS (tangent Z)
* Close
* Combo view > Data > Map path parameter = 0,5

[PAS_Drafter]

Well, that was even easier that I expected. There are so many little tricks like that, I don't know how anyone can learn (remember) them all

Thanks

[Bance]

It's in the Basic_Attachment_Tutorial