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Can somebody tell me the background why the residuals behave as to be seen in the attached picture ? All residuals make a smooth descend but just energy dissipation rate/frequency has data fluctuations ?
I have also attached the model. (.... maybe any hints for improvement ?)
Thx
Residuals
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Residuals
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- Air flow over one tank_flow characteristic.FCStd
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Re: Residuals
What is it? An empty wardrobe...
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Re: Residuals
Hi, yes I know I could have shorten the air flow space. The topic is to see how flow behaves in the trough in the middle. So despite this little clumsy figure could you give me some hints for improvement ? .... If I shorten the air space do I have to define the new face on the very top as wall with slip ? Because a wall with no slip would be obviousely wrong I guess.
Thx
Thx
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Re: Residuals
Thats what I did. The influence of the top wall is nearly zero, see velocity-arrows.Sidemountyucatan wrote: ↑Thu Dec 17, 2020 9:07 pm ... If I shorten the air space do I have to define the new face on the very top as wall with slip ?
...
I reduced the height of the model and used a little different mesh.
pressure at inlet/outlet = 0 (why do you define a pressure at the outlet?).
But: at iteration 150 I get the (first?) "omega-bump" like you. Mmmh...
However, runtime to reach 200 iterations was nearly 2 hours, I stopped the solver.
But the flow-field looks like what I would expect. Velocity at bottom nearly zero, a dust-trap.
At v-inlet = 0,2 m/s and box-length 1,2 m I get a Re=16000 for air. Thats not much.
Maybe a laminar approach does the work...
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Re: Residuals
Great ! Thx. I put the pressure to certain value because pressure 0 seemed to me physicaly wrong. Doesn't it imply vacuum ? Or is it kind of referenced pressure ?
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Re: Residuals
Set all inlet/outlet to pressure =0.Sidemountyucatan wrote: ↑Sat Dec 19, 2020 6:50 pm Great ! Thx. I put the pressure to certain value because pressure 0 seemed to me physicaly wrong. Doesn't it imply vacuum ? Or is it kind of referenced pressure ?
Example: airfoil
You will get negative pressure at certain zones. But this is physically impossible.
Solution: it is the pressure difference to the outside world.