**Moderator:** bernd

Harry how about fy for the test cases?

What do you mean Bernd? Fy = yield strength? Context?

I am writing a unit test for your rho calculstion def. input and output will be three or four posts before this post. But I need a yield strength too.

Sorry Bernd, I missed your question.

Sigma = sxx syy szz sxy sxz syz is input

Rho = rhox rhoy rhoz is output.

This can therefore only test the routine for calculating the reinforce ratio.

This assumes fy=500MPa and concrete tensile strength of 3MPa. I need to check how I accounted for the tensile strength in the verification code b

I am trying to do a few test cases but don’t know how to use the ReinforcedMaterial object. How do I link a steel and concrete object to this?

Like this:

there you have a normal material object and nog a reinfoced material object.

I found the original test file in the attic:HarryvL wrote: ↑Thu Apr 04, 2019 5:59 pmSorry Bernd, I missed your question.

Sigma = sxx syy szz sxy sxz syz is input

Rho = rhox rhoy rhoz is output.

This can therefore only test the routine for calculating the reinforce ratio.

This assumes fy=500MPa and concrete tensile strength of 3MPa. I need to check how I accounted for the tensile strength in the verification code b

I don't see if or how I accounted for tensile strength. Let me read the original article again, because I do reproduce the right output.

Ah I remember now. The reinforcement calculation ignores concrete tensile strength. Equilibrium at failure assumes the concrete is cracked and normal stress along the crack is taken by the steel in yield. The value of tensile strength in the article is only used in the crack width calculation. Something we may consider for future enhancement.