finding the App::Link of a selected object

[Zolko]

Hello,

I have an assembly with multiple linked parts in it (App::Link to App::Part), and when I select an object, either in the 3D window or in the tree, I would like to get the App::Link instance to which the selected object belongs. I know how to get the App::Part to which the selected object belongs with getParentGeoFeatureGroup() :

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selectedObj = Gui.Selection.getSelection()[0]
# loop until exhaustion or until we encounter an App::Part
parentPart = selectedObj
while parentPart:
    if parentPart.TypeId=='App::Part':
        break
    parentPart = parentPart.getParentGeoFeatureGroup()

But if I have included this App::Part multiple times with several App::Link instances, this always gives me the parent App::Part. What I would want is the particular App::Link instance in which I have selected the object.

Is there a (similar) way to get the App::Link where the selected object belongs ?

[DeepSOIC]

I think you need to use new selection API, probably Gui.Selection.getSelectionFromStack(). I don't know the details yet

[Zolko]

I have an assembly with multiple linked parts in it (App::Link to App::Part), and when I select an object, either in the 3D window or in the tree, I would like to get the App::Link instance to which the selected object belongs.

I think you need to use new selection API, probably Gui.Selection.getSelectionFromStack().

hi realthunder, may-be you know some more on this topic ?

ping

[realthunder]

If you want it for coding, there is App.getLinksTo(). Check the python docstring for more info.

If you want it as a command

Screenshot from 2019-12-05 18-38-50.png (35.65 KiB) Viewed 1915 times

[Zolko]

If you want it for coding, there is App.getLinksTo(). Check the python docstring for more info.

Thank-you, yes that works, but that's not the function I need. What I have is:

EDIT:

• an assembly (App::Part)
• that contains App::Links to other App::Parts
• one of these App::Parts contains an Body LCS (PartDesign::CoordinateSystem)
• this body has a solid made with PartDesign stuff
• this solid has a hole
• I have selected the edge of the hole with the mouse in the assembly window, in one of the instances of the App::Part (there are 2 App::Links pointing to the same App::Part)
• so I have selected a circular edge the LCS that belongs to an App::Link, which is a instance of the App::Part, either in the 3D window or the model tree

I know how to get the App::Part containing the Body LCS, but I need the particular App::Link that points to the App::Part. If I get the Name or the object itself doesn't matter. But there can be several other instances of the same App::Part.

[realthunder]

I know how to get the App::Part containing the Body LCS, but I need the particular App::Link that points to the App::Part. If I get the Name or the object itself doesn't matter. But there can be several other instances of the same App::Part.

Here is some code based on your description above. Assuming 'Assembly' is the give parent container.

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for obj in App.ActiveDocument.Assembly.Group:
	linked = obj.getLinkedObject()
	# if you accept both link and non-link, then delete the following two lines.
	if linked == obj:
		continue
	if not linked.isDerivedFrom('App::Part'):
		continue
	lcs = [ o for o in linked.Group if o.isDerivedFrom('PartDesign::CoordinateSystem') ]

If that's still not what you want, maybe you can provide an example file, and tell me which object you want to obtain given which object.

[Zolko]

If that's still not what you want, maybe you can provide an example file, and tell me which object you want to obtain given which object.

I'll try to describe with the model tree: I have an App::Part clled myPart in a document, that contains an LCS_0, a Body, and an LCS_1. I then have an assembly (it's an App::Part called Model) that has several LCS, and notably LCS_1 and LCS_2. I have inserted myPart twice into the assembly, the first one called myLink_1 and attached to LCS_1, and the second called myLink_2 and attached to LCS_2. Finallly, I have an LCS_3 in the assembly.

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myPart (App::Part)
  │
  ├─ LCS_0
  ├─ Body
  │    ├─ Sketch-1
  │    ├─ Extrusion
  │    ├─ Sketch-2
  │    └─ Extrusion
  └─ LCS_1

  
Model (App::Part)
  │
  ├─ LCS_0
  ├─ Sketch-1
  ├─ LCS_1
  ├─ LCS_2
  │
  ├─ myLink_1 (App::Link to myPart, attached to LCS_1)
  │    ├─ LCS_0
  │    ├─ Body
  │    │   ├─ Sketch-1
  │    │   ├─ Extrusion
  │    │   ├─ Sketch-2
  │    │   └─ Extrusion
  │    └─ LCS_1
  │
  ├─ myLink_2 (App::Link to myPart, attached to LCS_2)
  │    ├─ LCS_0
  │    ├─ Body
  │    │   ├─ Sketch-1
  │    │   ├─ Extrusion
  │    │   ├─ Sketch-2
  │    │   └─ Extrusion
  │    └─ LCS_1                            ← this is selected
  │
  └─ LCS_3

Now, I have selected, in the assembly window, the LCS_1 belonging to myLink_2. I am able to retrieve that it (the selected LCS_1) belongs to myPart, but what I would need to know is that I have selected the LCS_1 the belongs to the instance myLink_2 of myPart.

(because I want to attach, by its ExpressionEngine, LCS_3 of the assembly to the LCS_1 in myLink_2, therefore I need to know the Placement of LCS_1 in myPart → easy, and also the Placement of myLink_2 in the assembly → hard)

[alonso_jamm]

Now, I have selected, in the assembly window, the LCS_1 belonging to myLink_2. I am able to retrieve that it (the selected LCS_1) belongs to myPart, but what I would need to know is that I have selected the LCS_1 the belongs to the instance myLink_2 of myPart.

I have tried to do something like that before. I went to the source code of the selection api to found out that I could use

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Gui.Selection.getSelectionEx("", 0)[0].SubElementNames 

It returns a list separated with names separated by dots. The first name is the name of the linked part. However, if the linked part is a sub-assembly, then the first name will be the name of the sub-assembly.

I am not sure if this is exactly what you want, but it may be helpful.

[realthunder]

Now, I have selected, in the assembly window, the LCS_1 belonging to myLink_2. I am able to retrieve that it (the selected LCS_1) belongs to myPart, but what I would need to know is that I have selected the LCS_1 the belongs to the instance myLink_2 of myPart.

@alonso_jamm is right. Use Gui.Selection.getSelectionEx("",0). This gives you a list of selection with full object hierarchy, inside 'SubElementNames'. Select any object in tree view, and run the following code,

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for sel in Gui.Selection.getSelectionEx("",0):
	# sel.Object is the top parent object
	print(sel.Object.Name)
	for subname in sel.SubElementNames:
		print('\t' + subname)
		
		# getSubObjectList() split the subname with dots to obtain all
		# sub-objects in the path, including the top parent
		
		for obj in sel.Object.getSubObjectList(subname):
			print ('\t\t' + obj.Name)

[Zolko]

Code: Select all

Gui.Selection.getSelectionEx("", 0)[0].SubElementNames 

I am not sure if this is exactly what you want, but it may be helpful.

yes, this is exactly what I wanted, thank-you